Answer to Question #311552 in Physics for kelly

Question #311552

1. A voltage of 12 V is placed on a capacitor with C = 85 pF. (a) What is the charge on the capacitor? (b) How much energy is stored in the capacitor?


2. In open-heart surgery, a much smaller amount of energy will defibrillate the heart. (a) What voltage is applied to the 7 F capacitor of a heart defibrillator that stores 60.0 J of energy? (b) Find the amount of stored charge


3. Calculate the energy stored in a 5 μF capacitor charged to 30 V.


1
Expert's answer
2022-03-15T10:35:28-0400

1.

(a)


q=CV=85101212=1.02109Cq=CV\\ =85*10^{-12}*12=1.02*10^{-9}\:\rm C

(b)


W=CV22=8510121222=6.12109JW=\frac{CV^2}{2}\\ =\frac{85*10^{-12}*12^2}{2}=6.12*10^{-9}\:\rm J

2.


V=2W/C=260.0/7=4.14VV=\sqrt{2W/C}\\ =\sqrt{2*60.0/7}=4.14\:\rm V

3.


W=CV22=51063022=2.25103JW=\frac{CV^2}{2}\\ =\frac{5*10^{-6}*30^2}{2}=2.25*10^{-3}\:\rm J

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment