Question #311291

A solenoid is 3 cm long and has a radius of 0.50 cm. The wire carries 2.0 A of current. The magnetic field at the center is A. 0.0419 T b. 0.099 T C. 0.0013 T D. 20 T


1
Expert's answer
2022-03-18T12:00:52-0400

The magnetic field inside solenoid

B=μ0n4r2+l2IB=\mu_0 \frac{n}{\sqrt{4r^2+l^2}}I

B=4π×107×1/0.034×0.0052+0.032×2=0.0419TB=4\pi\times 10^{-7}\times \frac{1/0.03}{\sqrt{4\times 0.005^2+0.03^2}}\times2=0.0419\:\rm T

Answer: A. 0.0419 T


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