A solenoid is 3 cm long and has a radius of 0.50 cm. The wire carries 2.0 A of current. The magnetic field at the center is A. 0.0419 T b. 0.099 T C. 0.0013 T D. 20 T
The magnetic field inside solenoid
"B=\\mu_0 \\frac{n}{\\sqrt{4r^2+l^2}}I""B=4\\pi\\times 10^{-7}\\times \\frac{1\/0.03}{\\sqrt{4\\times 0.005^2+0.03^2}}\\times2=0.0419\\:\\rm T"
Answer: A. 0.0419 T
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