Question #311132

An object has a launch velocity of 30.0 m/s at launch angle of 30.00 relative to horizontal. Find the a) x and y component of initial velocity, b) time to reach the peak c) total time of flight, d) vertical height to reach the peak, and e) horizontal distance. 


1
Expert's answer
2022-03-14T09:45:42-0400

a)

v0x=v0cosθ=30.0cos30.0=26.0m/sv_{0x}=v_0\cos\theta\\ =30.0\cos30.0^\circ=26.0\:\rm m/s

v0y=v0sinθ=30.0sin30.0=15.0m/sv_{0y}=v_0\sin\theta\\ =30.0\sin30.0^\circ=15.0\:\rm m/s

b)

t1=v0yg=26.09.81=2.65st_1=\frac{v_{0y}}{g}=\frac{26.0}{9.81}=2.65\:\rm s

c)

t2=2v0yg=226.09.81=5.30st_2=\frac{2v_{0y}}{g}=\frac{2*26.0}{9.81}=5.30\:\rm s

d)

hmax=v0y22g=26.0229.81=34.5mh_{\max}=\frac{v_{0y}^2}{2g}=\frac{26.0^2}{2*9.81}=34.5\:\rm m

e)

R=v0xt2=15.05.30=79.5mR=v_{0x}t_2=15.0*5.30=79.5\:\rm m


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS