Question

A body moving with an initial velocity 6ms~-¹ accelerates uniformly at a rate of 50ms~-¹.What is the distance covered during this period

Answer 1

The distance traveled by a body

$$d=v_0t+\frac{at^2}{2}$$

For the time $t=4\:\rm s$ we obtain

$$d=6*4+\frac{50*4^2}{2}=124\:\rm m$$