Question #310855

Instructions: Show the whole solutions in each question.



1. Determine the net capacitance of the capacitor combination when the capacitances are C1=12µF, C2=2µF, C3=4µF When the 12V potential difference is maintained across the combination, find the charge and the voltage across each capacitor.



2. Compute the capacitance of a capacitor with two parallel plates and separated by a layer of paraffin that is 0.25cm thick. The area of each plate is 70cm^2, and the dielectric constant of paraffin is 2.

1
Expert's answer
2022-03-13T18:46:15-0400

1. The net capacitance

1C=1C1+1C2+1C3\frac{1}{C}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}

1C=112μF+12μF+14μF\frac{1}{C}=\frac{1}{12\:\rm \mu F}+\frac{1}{2\:\rm \mu F}+\frac{1}{4\:\rm \mu F}

C=1.2μFC=1.2\:\rm \mu F

The charge at the plates of capacitors

q1=q2=q3=CV=1.210612=14.4μCq_1=q_2=q_3=CV\\ =1.2*10^{-6}*12=14.4\:\rm \mu C

The voltage

V1=q1/C1=14.4/12=1.2VV_1=q_1/C_1=14.4/12=1.2\:\rm V

V2=q2/C2=14.4/2=7.2VV_2=q_2/C_2=14.4/2=7.2\:\rm V

V3=q3/C3=14.4/4=3.6VV_3=q_3/C_3=14.4/4=3.6\:\rm V

2. The capacitance of a parallel plate capacitor


C=κϵ0Ad=28.851012701040.25102=501012F=50pFC=\frac{\kappa\epsilon_0A}{d}\\ =\frac{2*8.85*10^{-12}*70*10^{-4}}{0.25*10^{-2}}=50*10^{-12}\:\rm F=50\: pF

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS