Answer to Question #310839 in Physics for Itachi

Question #310839

Three forces of magnitude 6N,2N,3N act on a small object in directions north,south and west respectively. Find the direction and magnitude of the resultant force.If the force to move and its mass is 0.2kg.Calculate the initial acceleration.

1
Expert's answer
2022-03-13T18:46:21-0400

Given:

F1=6NF_1=\rm 6\: N

F2=2NF_2=\rm 2\: N

F3=3NF_3=\rm 3\: N

The net force

F=(F1F2)2+F32=(62)2+32=5NF=\sqrt{(F_1-F_2)^2+F_3^2}\\ =\sqrt{(6-2)^2+3^2}=5\:\rm N

The direction

θ=tan143=53  N  of  W\theta=\tan^{-1}\frac{4}{3}=53^\circ\; \rm N\; of\; W

The acceleration

a=Fm=5N0.2kg=25m/s2a=\frac{F}{m}=\frac{5\:\rm N}{0.2\:\rm kg}=25\:\rm m/s^2


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