Answer to Question #310837 in Physics for Itachi

Question #310837

The air pressure at the base of a mountain is 75.0cm of mercury. Given that the average density of air is 1.25kg/m³ and the density of mercury is 13600kg/m³,calculate the height of the mountain. [Take g=10m/s²]

Expert's answer

The hydrostatic pressure is given by

p=g\rho h

g\rho_{\rm Hg}h_{\rm Hg}=g\rho_{\rm Air}h_{\rm Air}

Hence

h_{\rm Air}=\frac{\rho_{\rm Hg}h_{\rm Hg}}{\rho_{\rm Air}}

h_{\rm Air}=\frac{1360\rm \: kg/m^3*0.75\rm \: m}{1.25\rm \: kg/m^3}=8160\:\rm m

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Victor Ouma

17.07.23, 00:18

Good

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