Question

A man with a mass of 50kg rides a Ferris wheel of radius 10 meters rotating in a vertical circle at a constant speed of 3.0 m/s. The normal force on the man from the seat when the man is at its lowest point.

Answer 1

The normal force reaction at lowest point is given by

$$N=m(g+a)$$

The centripetal acceleration

$$a=\frac{v^2}{R}$$

Finally

$$N=m\left(g+\frac{v^2}{R}\right)$$ $$N=50\left(9.8+\frac{3.0^2}{10}\right)=535\: \rm N$$