Answer to Question #309385 in Physics for ake342s

Question #309385

A car approaches a stop sign going 5 m/s before it comes to a stop. If it does this in 4 seconds, what was its acceleration?


1
Expert's answer
2022-03-10T18:00:47-0500

The acceleration of the car

a=ΔvΔta=\frac{\Delta v}{\Delta t}

a=0m/s5m/s4s=1.25m/s2a=\rm\frac{0\: m/s-5\: m/s}{4\: s}=-1.25\: m/s^2


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