Question

A capacitor has a charge of 9 microcoulomb when connected with a 12 V battery. Determine the capacitance.

Answer 1

The capacitance is given as follows:

$$C = \dfrac{Q}{V}$$

where $Q = 9\times 10^{-9}C, V = 12V$. Thus, obtain:

$$C = \dfrac{9\times 10^{-9}C}{12V} = 7.5\times 10^{-10}F$$

Answer. $7.5\times 10^{-10}F$.