Question

What is the capacitance of a capacitor that stores 50 picocoulomb of charge when connected to a 4 V battery?

Answer 1

The capacitance is given as follows:

$$C = \dfrac{Q}{\Delta V}$$

where $Q = 50\times 10^{-12}C, \Delta V = 4V$. Thus, obtain:

$$C = \dfrac{50\times 10^{-1}C}{4V} = 12.5\times 10^{-12}F$$

Answer. $12.5\times 10^{-12}F$.