Question

How much charge flows from each terminal of a 12.0-V battery when it is connected to a 5.00-μF capacitor?

Answer 1

The charge is given as the product of capacitance and voltage:

$$Q= CV = 5\times 10^{-6}F\cdot 12V = 2.160\times 10^{-2}C = 60.0\times 10^{-6}C$$

Answer. $6.00\times 10^{-5}C$.