Question

Suppose there is an isolated charge A B

(+1.5𝑥10−19𝐶) that is displaced from point

A to B due to the electric force. As the

charge moves, it produces an electric field

which has a magnitude of 6.9 N/C. Find

the work done by the electric force of the

charge if it moves 1.5 m from its original

position.

Answer 1

The work done by an electric field

$$W=qEd\\ =\rm 1.5*10^{-19}\: C*6.9\: N/C*1.5\: m=1.6*10^{-18}\: J$$