Answer to Question #307865 in Physics for mike

Question #307865

A light ray strike an air/water surface at an angle of 46 degrees with respect of the normal. find the angle of refraction when the direction of the ray is from the air to water

1
Expert's answer
2022-03-08T08:56:56-0500

The Snell's law says


nisinθi=nrsinθrn_i\sin\theta_i=n_r\sin\theta _r

Thus


θr=sin1(ninrsinθi)\theta_r=\sin^{-1}\left(\frac{n_i}{n_r}\sin\theta_i\right)θr=sin1(1.001.43sin46)=30\theta_r=\sin^{-1}\left(\frac{1.00}{1.43}\sin46^\circ\right)=30^\circ

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