Answer to Question #307780 in Physics for yourme

Question #307780

A closed surface which encloses a charge has an electric flux of 15.8 N.m^2/C. What is the magnitude of the charge?

Expert's answer

The electric flux through surface

"\\Phi=\\oint EdA=\\frac{q}{\\epsilon_0}"

Hence, the net charge

"q=\\Phi \\epsilon_0\\\\\n=15.8*8.85*10^{-12}=1.4*10^{-10}\\:\\rm C"

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