Question #307555

A bucket full of water and weighing 200N is supported by two men holding the handle at each side, each pulling sideways at an angle of 30° to the vertical. Find the force in each man's arm.

1
Expert's answer
2022-03-08T08:55:58-0500

At the equilibrium

mg=2Fcos30mg=2F\cos30^\circ

The force in each man's arm

F=mg2cos30=200N23/2=115NF=\frac{mg}{2\cos30^\circ}=\frac{200\:\rm N}{2*\sqrt{3}/2}=115\: \rm N


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