Question

A 200 g object is whirled in a horizontal circle with a cord of radius 1.2 m at 2261.95 cm/s. The centripetal acceleration is .

Answer 1

The centripetal acceleration is given as follows:

$$a= \dfrac{v^2}{R}$$

where $v = 2261.95cms = 22.6195m/s$ is the speed, and $R = 1.2m$ is the radius of the circle. Thus, obtain:

$$a = \dfrac{(22.6195m/s)^2}{1.2} \approx 430 m/s^2$$

Answer. 430 m/s^2.A