Question

What changes take place in the atomic structure of an element X with atomic number 88 and mass number 226,if it emits 2 alpha particles

Answer 1

The atomic number of alpha particle is 2 (Helium), and the mass number is 4. Thus, the  atomic number of element X will be reduced by 4 (since two alpha particle were emited):

$$88-4 = 84$$

and the mass number will be reduced by 8:

$$226-8 = 218$$

Answer. Atomic number of the new element is 84, and mass number is 218.