Question #305222

Water flowing over the Wraith Falls in Yellowstone National Park drops 30 m.

 If all of the water's energy goes to heat it, what is its temperature increase?


Expert's answer

Let all potential energy be converted to heat energy:


mgh=mcΔTmgh=mc\Delta T

where mm is the mass of water, g=9.8m/s2g = 9.8m/s^2 is the gravitational acceleration, h=30mh=30m is the height, c=4200J/kg/°Cc = 4200J/kg/\degree C is the specific heat capacity of water, ΔT\Delta T increase in temperature. Thus, obtain:


ΔT=ghc=9.8m/s230m4200J/kg/°C=0.07°C\Delta T = \dfrac{gh}{c} = \dfrac{9.8m/s^2\cdot 30m}{4200J/kg/\degree C} = 0.07\degree C

Answer. 0.07°C0.07\degree C.


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