Question #304978

 A uniform electric field is directed to the right and has a magnitude of 8 N/C. Find the magnitude and direction of the force experienced by a 10 nC test charge placed in this field.


Expert's answer

F=qE=101098=80109NF=qE=10*10^{-9}*8=80*10^{-9}\:\rm N

Force is directed to the right.


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