Question

acceleration of a car that comes to a stop from a velocity of 60 m/s in a distance of 360 m

Answer 1

Using the kinematic formula (see https://www.khanacademy.org/science/physics/one-dimensional-motion/kinematic-formulas/a/what-are-the-kinematic-formulas), obtain:

$$v^2 = v_0^2-ad$$

where $v=0,v_0=60m/s$ are the final and initial velocities respectively, $d = 360m$ is the distance, and $a$ is the acceleration (- sign since the car comes to stop). Thus, obtain:

$$a = \dfrac{v_0^2}{d} = \dfrac{60^2}{360} = 10m/s^2$$

Answer. 10m/s^2.