Question

What charge is stored in a 180.0-$\mu$F capacitor when 120.0 V is applied to it

Answer 1

The charge is given as the product of capacitance and voltage:

$$Q= CV = 180\times 10^{-6}F\cdot 120V = 2.160\times 10^{-2}C$$

Answer. $2.160\times 10^{-2}C$.