Answer to Question #304104 in Physics for tim

Question #304104

The temperature coefficient of resistivity of carbon is - 0.0005/C°.if the resistor is made of graphite has a resistance of 5 k $\Omega$ at 20° find the resistance at 27°

Expert's answer

R(t_2)=R(t_1)(1+\alpha(t_2-t_1))

R(27)=R(20)(1+\alpha(27-20))

R(27)=5000\:\Omega(1+(- 0.0005)*7)=4983\:\Omega

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