Question

Solve for the Electric field of a point charge q, with a value of 2.9 nC and a distance of 2.4 m

Answer 1

The electric field of a point charge

$$E=k\frac{q}{r^2}=9*10^9*\frac{2.9*10^{-9}}{2.4^2}=4.5\:\rm N/C$$