Question

A 55000.kg truck rounds a 38.0 m radius curve at 62.0km/h. Find how much centripetal force must be supplied by friction with the road to keep the truck from from slipping

Answer 1

The centripetal force

$$F=\frac{mv^2}{r}\\ =\rm\frac{55000\: kg*(17.2\: m/s)^2}{38.0\: m}=4.29*10^5\: N$$