Question #302942

How many seconds would it take for a 4.50kW motor to raise a 175.kg boiler to a height of 15.0 m?

Expert's answer

t=WP=175kg9.8N/kg15.0m4500W=5.72st=\frac{W}{P}\\ =\rm\frac{175\: kg*9.8\: N/kg*15.0\: m}{4500\: W}=5.72\: s


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