Question #301639

A car starts from the rest covers a distanc 500m while accelerating uniformly at 10m/s2.


Expert's answer

Given:

v0=0v_0=0

d=500md=500\:\rm m

a=10m/s2a=10\:\rm m/s^2


The final velocity

v=v02+2ad=02+210500=100m/sv=\sqrt{v_0^2+2ad}=\sqrt{0^2+2*10*500}=100\:\rm m/s


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