Question

A ball is thrown with an initial velocity of 36 m/s at 33°.

What is the initial velocity of the ball at x ang y-dimension?

What is the final velocity of the ball at x and y- dimension?

What is the time of the ball as it reaches its peak?

What is the maximum height reached of the ball?

What is the total time travel of the ball?

Answer 1

Given:

$v_0=36\;\rm m/s$

$\theta=33^\circ$

What is the initial velocity of the ball at x ang y-dimension?

$$v_{0x}=v_0\cos\theta=30.2\:{\rm m/s}\\ v_{0y}=v_0\sin\theta=19.6\:\rm m/s$$

What is the final velocity of the ball at x and y- dimension?

$$v_{fx}=v_{0x}=30.2\:{\rm m/s}\\ v_{fy}=-v_{0y}=-19.6\:\rm m/s$$

What is the time of the ball as it reaches its peak?

$$t=\frac{v_{0y}}{g}=\frac{19.6}{9.8}=2.0\: \rm s$$

What is the maximum height reached of the ball?

$$h_{\max}=\frac{v_{0y}^2}{2g}=19.6\:\rm m$$

What is the total time travel of the ball?

$$t_{tot}=2*2.0\: \rm s=4.0\: s$$