Question #301443

If in the process oof rubbing the lenses of the eyeglasses, 6.28 x 10^10 electrons were transferred,


a) what is the charge of the lenses and the nylon cloth?


b) what is the change in their masses?

1
Expert's answer
2022-02-23T08:31:16-0500

The charge of the lenses (glass) is positive


q1=eN=1.6×1019C×6.28×1010=1.00×108Cq_1=eN\\ =1.6\times 10^{-19}\:\rm C\times 6.28\times 10^{10}=1.00\times 10^{-8}\:\rm C

The charge of the nylon cloth is negative


q2=eN=1.6×1019C×6.28×1010=1.00×108Cq_2=-eN\\ =-1.6\times 10^{-19}\:\rm C\times 6.28\times 10^{10}=-1.00\times 10^{-8}\:\rm C


The change in mass

Δm=Nme=6.2810109.11031kg=5.711020kg\Delta m=Nm_e\\ =6.28*10^{10}*9.1*10^{-31}\:\rm kg=5.71*10^{-20}\: kg

The lenses lose, the nylon cloth gains.


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