Question

What will be the final temperature if a 4 x 10⁷ J of heat is transferred to a 1 kg block of aluminum initially at 20°C

Answer 1

Given:

$Q=4*10^7\:\rm J$

$m=1\:\rm kg$

$t_i=20\:\rm {^\circ C}$

$c=890\:\rm J/kg\cdot K$

The amount of heat

$$Q=cm\Delta t$$

Hence, the final temperature of a block

$$t_f=t_i+Q/cm\\ =20+4*10^7/(890*1)=44964 \:\rm {^\circ C}$$

The obtained result is too large. Please check your given.