Question #300183

How many seconds would it take for a 4.50kw motor to raise a 175.kg boiler to a height of 15.0m?

1
Expert's answer
2022-02-20T15:45:06-0500

Given:

P=4.50kWP=4.50\:\rm kW

m=175kgm=175\:\rm kg

h=15.0mh=15.0\:\rm m


The required time

t=WP=mghP=1759.815.04500=5.72st=\frac{W}{P}=\frac{mgh}{P}=\frac{175*9.8*15.0}{4500}=5.72\:\rm s


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS