A copper road whose length at 70°c is 4.0m is heated to 10°c find it
Given:
l0=4.0 ml_0=4.0\;\rm ml0=4.0m
ΔT=30 K\Delta T=30\:\rm KΔT=30K
α=17∗10−6 K−1\alpha=17*10^{-6}\:\rm K^{-1}α=17∗10−6K−1
The thermal linear expansion is described by an equation
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