Question #299801

2. Four charges. q, 5.00 x10'C. q-3.00 x C. q-2.00 x10°C. -6.00 x10 C, are situated at the corners of a square of side 4.00m. Find the potential at the center of the square?


1
Expert's answer
2022-02-20T15:45:15-0500

Given:

q1=5.00107C,q2=3.00107Cq_1=5.00*10^{-7}\:{\rm C},\quad q_2=-3.00*10^{-7}\:\rm C

q3=2.00107C,q4=6.00107Cq_3=-2.00*10^{-7}\:{\rm C},\quad q_4=6.00*10^{-7}\:\rm C

r=224.00m=2.83mr=\frac{\sqrt{2}}{2}*4.00\:\rm m=2.83\: m


The net potential at the center of square


V=V1+V2+V3+V4V=V_1+V_2+V_3+V_4V=kr(q1+q2+q3+q4)V=\frac{k}{r}(q_1+q_2+q_3+q_4)V=91092.83(5.003.002.00+6.00)107=1910VV=\frac{9*10^9}{2.83}(5.00-3.00-2.00+6.00)*10^{-7}=1910\:\rm V

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