Question #299658

Find the acceleration of a 1500.kg car, driven by 2200.N against 450.N of friction

1
Expert's answer
2022-02-18T15:53:08-0500

Given:

m=1500kgm=1500\:\rm kg

F=2200NF=2200\:\rm N

Ff=450NF_f=450\:\rm N


The Newton's second law says

a=Fnetm=FFfma=\frac{F_{net}}{m}=\frac{F-F_f}{m}

a=22004501500=1.17m/s2a=\frac{2200-450}{1500}=1.17\:\rm m/s^2


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