Question #299597

A stone is thrown straight upwards and it rises to a maximum height of 20m. With what speed was it thrown?

Expert's answer

The maximum height

hmax=v022gh_{\max}=\frac{v_0^2}{2g}

The initial speed

v0=2ghmax=29.820=19.8m/sv_0=\sqrt{2gh_{\max}}=\sqrt{2*9.8*20}=19.8\:\rm m/s


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