Answer to Question #299569 in Physics for Totti

Question #299569

Calculate the change in temperature of an 900mm aluminium bar, that has increased in length to 901.035mm.

 α = 25 x 10-6k-1

1
Expert's answer
2022-02-20T08:20:52-0500

Given:

l0=900mml_0=900\:\rm mm

α=25106K1\alpha=25*10^{-6}\:\rm K^{-1}

l=901.035mml=901.035\:\rm mm


The thermal expansion is described by an equation


Δl=l0αΔt\Delta l=l_0\alpha\Delta tΔt=Δlαl0=901.03590025106900=46C\Delta t=\frac{\Delta l}{\alpha l_0}\\ =\rm \frac{901.035-900}{25*10^{-6}*900}=46\:{^\circ C}

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