Calculate the change in temperature of an 900mm aluminium bar, that has increased in length to 901.035mm.
α = 25 x 10-6k-1
Given:
l0=900 mml_0=900\:\rm mml0=900mm
α=25∗10−6 K−1\alpha=25*10^{-6}\:\rm K^{-1}α=25∗10−6K−1
l=901.035 mml=901.035\:\rm mml=901.035mm
The thermal expansion is described by an equation
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