Question

the energy used by an electric iron for 1 minute is 33 kJ, at a voltage of 220 volts. How large the current is in the electric iron?

Answer 1

Given:

$t=60\:\rm s$

$W=33000\:\rm J$

$V=220\;\rm V$

The work done by electric field

$$W=IVt$$

Thus, the electric current

$$I=\frac{W}{Vt}=\frac{33000}{220*60}=2.5\: \rm A$$