Question #298429

In a series of 2ohms,4ohms,3ohms,2ohms,4ohms and 3voltage find the current in the circuit


Expert's answer

The Ohm's law says

I=VRnetI=\frac{V}{R_{\rm net}}

In our case

I=3V(2+4+3+2+4)Ω=0.2AI=\frac{3\:\rm V}{\rm(2+4+3+2+4)\:\Omega}=0.2\:\rm A


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