Question

Air at 5 atm is compressed to half of its original volume. Find the resulting pressure of the air.

Answer 1

The Boyle–Mariotte law says

$$p_1V_1=p_2V_2$$

Thus, the resulting pressure

$$p_2=p_1\frac{V_1}{V_2}=\rm 5\: atm*\frac{V_0}{1/2V_0}=10\: atm$$