Answer to Question #297999 in Physics for Eldy

Question #297999

Air at 5 atm is compressed to half of its original volume. Find the resulting pressure of the air.

Expert's answer

The Boyle–Mariotte law says

"p_1V_1=p_2V_2"

Thus, the resulting pressure

"p_2=p_1\\frac{V_1}{V_2}=\\rm 5\\: atm*\\frac{V_0}{1\/2V_0}=10\\: atm"

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