Question #297583

A 2 KG MASS AND A 3 KG MASS ARE ATTACHED TO A LIGHT WEIGHT CORD THAT PASSES OVER A FRICTIONLESS PULLEY. THE HANGING MASSES ARE LEFT FREE TO MOVE. FIND THE


A. ACCELERATION

B. TENSION OF THE CORD


1
Expert's answer
2022-02-18T08:23:12-0500

Given:

m1=2kgm_1=\rm 2\: kg

m2=3kgm_2=\rm 3\: kg


(a) The acceleration of system



a=gm2m1m2+m1=9.8323+2=2m/s2a=g\frac{m_2-m_1}{m_2+m_1}=9.8*\frac{3-2}{3+2}=2\:\rm m/s^2


(b) The tension in cord


T=m2(ag)=3(9.82)=24NT=m_2(a-g)=3(9.8-2)=24\:\rm N

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