Question

A lead pellet is propelled vertically upward by an air rifle with an initial speed of 50 ft/s. Find its maximum height ?

Answer 1

Given:

$v_0=50\:\rm ft/s$

$g=32.17\:\rm ft/s^2$

The maximum height

$$h_{\max}=\frac{v_0^2}{2g}=\frac{50^2}{2*32.17}=39\:\rm ft$$