Question #296868

An oscillatory body of mass In attached to a spring of stiffness constant s performs simple harmonic motion in the x-direction. Show that the oscillation is described by the equation mx + sx =0


1
Expert's answer
2022-02-13T12:15:25-0500


The Newton's second law says

ma=Fma=F

In our case

ma=sxma=-sx

The acceleration

a=xa=x''

Finally, we obtain an equation

mx+sx=0mx''+sx=0


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