Question #296720

1. An elevator cab that weighs 27.8 kN moves upward. What is the tension in the cable if the cab’s speed is ___.



Find the mass of the elevator:


a. At rest


b. Uniform motion


c. Increasing at a rate of 1.2m/s2


d. Decreasing at the rate of 1.2m/s2




Please give me a solution and formula by letters. Thank you!


1
Expert's answer
2022-02-13T12:14:43-0500

Given:

W=27.8103NW=27.8*10^3\:\rm N


The tension in cable


T=W+maT=W+ma

a. a=0a=0

T=W=27.8kNT=W=27.8\rm \: kN

b. a=0a=0

T=W=27.8kNT=W=27.8\rm \: kN

c. a=1.2m/s2a=1.2\:\rm m/s^2

T=W+ma=27.8kN+27.8kN9.8N/kg1.2m/s2=31200NT=W+ma\\ =27.8\rm \: kN+\frac{27.8\rm \: kN}{9.8\:\rm N/kg}*1.2\:m/s^2=31200\:\rm N

d. a=1.2m/s2a=-1.2\:\rm m/s^2

T=W+ma=27.8kN27.8kN9.8N/kg1.2m/s2=24396NT=W+ma\\ =27.8\rm \: kN-\frac{27.8\rm \: kN}{9.8\:\rm N/kg}*1.2\:m/s^2=24396\:\rm N

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