Question

A force of 500 N acts horizontally on a load at rest on the floor. The load moves a distance of 20 m in 10 s. What is the amount of power?

Answer 1

Given:

$F=500\:\rm N$

$d=20\:\rm m$

$t=10\:\rm s$

The power

$$P=\frac{W}{t}=\frac{Fd}{t}$$

$$P=\rm\frac{500\: N*20\: m}{10\: s}=1000\:\rm W$$