A point of charge 10×10^-6C has a potential of 4×10^4V from a point 2mm from it. Calculate the potential due to the charge when the distance is now 16mm.
Given:
V1=4∗104 VV_1=4*10^4\:\rm VV1=4∗104V
r1=2∗10−3 mr_1=2*10^{-3}\:\rm mr1=2∗10−3m
r2=16∗10−3 mr_2=16*10^{-3}\:\rm mr2=16∗10−3m
The potential of electric field of point charge
Hence
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