Answer to Question #296416 in Physics for Blossom

Question #296416

A point of charge 10×10^-6C has a potential of 4×10^4V from a point 2mm from it. Calculate the potential due to the charge when the distance is now 16mm.

1
Expert's answer
2022-02-11T08:48:38-0500

Given:

V1=4104VV_1=4*10^4\:\rm V

r1=2103mr_1=2*10^{-3}\:\rm m

r2=16103mr_2=16*10^{-3}\:\rm m


The potential of electric field of point charge

V=kqr1rV=k\frac{q}{r}\sim\frac{1}{r}

Hence

V2=V1r1r2=41040.0020.016=5000VV_2=V_1\frac{r_1}{r_2}=4*10^4*\frac{0.002}{0.016}=5000\:\rm V


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