Answer to Question #294923 in Physics for hhaha

Question #294923

How much work is done on the block if a 10.0 kg block was accelerated at 5.0 m/s2 with a distance of 2.5 m across a frictionless table?


1
Expert's answer
2022-02-07T14:02:58-0500

Given:

m=10.0kgm=10.0\:\rm kg

a=5.0m/s2a=5.0\:\rm m/s^2

d=2.5md=2.5\:\rm m


The force acting on a block


F=ma=10.0kg5.0m/s2=50.0NF=ma=\rm 10.0\: kg*5.0\: m/s^2=50.0\: N

The work done


W=Fd=50.0N2.5m=125JW=Fd=\rm 50.0\: N*2.5\: m=125\: J

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