How much work is done on the block if a 10.0 kg block was accelerated at 5.0 m/s2 with a distance of 2.5 m across a frictionless table?
Given:
m=10.0 kgm=10.0\:\rm kgm=10.0kg
a=5.0 m/s2a=5.0\:\rm m/s^2a=5.0m/s2
d=2.5 md=2.5\:\rm md=2.5m
The force acting on a block
The work done
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