Answer to Question #294899 in Physics for Njkmnnn

Question

Calculate the pressure exerted by a 0.25 mole sulfur hexafluoride in a steel vessel having a capacity of 1250 ml at 70.0°C

Answer 1

Given:

$n=0.25\:\rm moles$

$V=\rm 1250\: ml=1.25*10^{-3}\: m^3$

$T=t+273=343\: \rm K$

The equation of state for ideal gas says

$p=\frac{nRT}{V}=\frac{0.25*8.31*343}{1.25*10^{-3}}=5.70*10^5\:\rm Pa$