Question

A gas occupies a volume of 50 mL at a temperature of 0°C and a pressure of 2,000 N / m³. What volume will be occupied by the same amount of gas also at 0°C if the pressure is increased to 10,000 N / m³.

Answer 1

Given:

$V_1=\rm 50\: mL$

$p_1=\rm 2000\: N/m^2$

$p_2=\rm 10000\: N/m^2$

$V_2-?$

The Boyle–Mariotte law says

$$p_1V_1=p_2V_2$$

Hence

$$V_2=V_2\frac{p_1}{p_2}$$

$$V_2=50\:\rm mL*\frac{2000\: N/m^2}{10000\: N/m^2}=10\: mL$$