Question

If a 10 kg object is moving at 5 m/s what force is required to maintain it the force is required to stop it in two seconds

Answer 1

Given:

$m=10\:\rm kg$

$v_i=\rm 5\: m/s$

$v_f=\rm 0\: m/s$

$\Delta t=2\:\rm s$

The Newton's second law says

$$F=ma=m\frac{\Delta v}{\Delta t}$$

$$F=\rm 10\: kg*\frac{5\: m/s}{2\: s}=25\: N$$