Answer to Question #294179 in Physics for Giana Perasi

Question #294179

A 100-g body is attached at the end of a hanging spring constant of 2,000 dynes/cm. It is displaced 10 cm from it's equilibrium position and then released. Calculate the period (T). Find the maximum acceleration of the body. Find the acceleration of the body when it is 5 cm from the equilibrium position


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Expert's answer
2022-02-05T10:26:38-0500
T=2πm/k=1.4 s.amax=ω2A=(k/m)2A=40 m/s2.a(5)=amaxcos(ωt)=6.9 m/s2.T=2\pi\sqrt{m/k}=1.4\text{ s}.\\ a_\text{max}=\omega^2A=(k/m)^2A=40\text{ m/s}^2.\\ a(5)=a_\text{max}\cos(\omega t)=-6.9\text{ m/s}^2.


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